2 gooey hydrocarbons A and B respectively C6H6 be used surrounded by exp. A decoulrises Br hose down swiftly, B reactd terrifically slowly
Question: Two liquid hydrocarbons A and B respectively C6H6 were used contained by an experiment. A decolourises bromine water speedily whereas B reacted unbelievably slowly
- draw possible structures for A and B
- explain why B reacted exceedingly slowly.
Answers:
B is benzene which does not react as an unsaturated compound.
A contains double or triple bonds and is some isotope of an aliphatic six carbon compoud near several double and triple bond possibilities.
One is defiantly benzene. The other is 1,5-Hexene-3yne
Scott S have acceptable answers here. The root the alkyne can readily decolorize the solution is that bromine can readily react near the sites of unsaturation (multiple bonds) in a typical enhancement reaction (in the presence of light). To attach bromine to benzene, however, FeBr3 needs to also be present. This would explain why benzene, B, does not act in response very much if at adjectives.
A = Benzene
The 6 carbons form a hexagon (so there is one covalent bond between them) and respectively carbon has one hydrogen attached to it. The finishing electron roves around and is generally drawn as the double bond between every other carbon.
A decolorises bromine due to the saturation of the double bonds:
C6H6 + 3Br2 --> C6H6Br6
This is an assimilation reaction and also a testing for unsaturated double bonds.
B = CH3 - C -triple bond- C - C triple bond- C - CH3
Alkynes do not react as slickly as double bonds.
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