Can you guys please back me match this equation: C2H6 (g) + O2 → CO2 (g) + H2O (l)?
Question:
Answers:
2C2H6(g) + 7O2(g)= 4CO2(G) + 6H2O(l)
173
2C2H6 + 7O2 -> 4CO2 + 6H2O
C2H6 + 3.5O2 --> 2CO2 + 3H2O
OR
2C2H6 + 7O2 ---> 4CO2 + 6H2O
2C2H6 + 7O2 = 4CO2 + 6H2O
18,200 J is the total answere as it is a question that take numerous equations to sort out but when all the equations are deal with and the answeres of adjectives them then equated the final answere is 18,200 j as if you google it you will find out.
C2H6+3/2O2=2CO2+3H20
2 C2H6 + 7 O2 ---> 4 CO2 + 6 H2O
2C2H6(g) + 7O2 ---> 4CO2(g) + 6H2)(l)
2 C2H6 (g) + 7 O2 -> 4 CO2 (g) + 6 H2O (l)
or if you adjectives divide with 2 later:
C2H6 (g) + 7/2 O2 -> 2 CO2 (g) + 3 H2O (l)
C2H6 + O2 = CO2 + H2O
C2H6 + 7/2O2 = 2CO2 + 3H2O
But chemists don't like 'half' values surrounded by equations So!
2C2H6 + 7O2 = 4CO2 + 6H2O
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